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Joined: Oct '09
Location: Spain
Age: 60 (M)
Posts: 2851
I use a formula to generate my numbers:
•The expected value of a constant, α, is the constant: E[α]=α (3) •Adding a constant, α, to each term increases the expected value by that constant: E[X+α]=E[X]+α (4) •Multiplying the random variable by a constant, α, multiplies the expected value by that constant. E[αX]=αE[X] (5) •The expected value of the sum of two or more random variables, is the sum of each individual expected value. E[X+Y]=E[X]+E[Y]
X = E[X] = 1 T ∫0TX(t)dt
First, we will use Equation 1 to solve for the mean value.
X = ∫1020x1 10 dx = 1 10 (x22 )|x=1020 = 1 10 (200−50) = 15 (19) Using Equation 7 we can obtain the mean-square value for the above function. X2 = ∫1020x21 10 dx = 1 10 (x3 3)|x=1020 = 1 10 (8000 5000 3 ) = 233.33 (20)
And finally, let us solve for the variance of this function. σ2 = X2−(X)2 = 233.33−152 = 8.33
Joined: May '08
Location: Sweden
Age: 55 (M)
Posts: 1362
Yeah, what if someone steals my number, that hasn't come up for like three years? It's bound to do so any day, so there's no way I'm telling you it's 911!!
(The number in the post above has been edited, to be sure of it's anonymity...)
Can't say my favourite number because I change it everyday. I'm using a strategy to crack it and, when I will manage to do it, I will post. For now, no results
